3d^2-13d-10=0

Solution for 3d^2-13d-10=0 equation:

3d^2-13d-10=0

a = 3; b = -13; c = -10;
Δ = b2-4ac
Δ = -132-4·3·(-10)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-17}{2*3}=\frac{-4}{6}
=-2/3
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+17}{2*3}=\frac{30}{6}
=5
$